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Area of rhombus = 1/2 (Product of the di...

Area of rhombus `= 1/2` (Product of the diagonals)

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Find the area of a rhombus if its vertices are (3, 0), (4, 5), (-1, 4) and (-2, -1) taken in order. [Hint : Area of a rhombus = (1)/(2) (product of its diagonals)].

Show that the points (-4, -7), (-1, 2), (8, 5) and (5, -4) taken in order are the vertices of a rhombus. Find its area. (Hint : Area of rhombus = (1)/(2)xx product of its diagonals)

Show that the points (-4, -7), (-1, 2), (8, 5) and (5, -4) taken in order are the vertices of a rhombus. Find its area. (Hint : Area of rhombus = (1)/(2)xx product of its diagonals)

Show that the points (-4, -7), (-1, 2), (8, 5) and (5, -4) taken in order are the vertices of a rhombus. Find its area. (Hint : Area of rhombus = (1)/(2)xx product of its diagonals)

Show that the points (-4, -7), (-1, 2), (8, 5) and (5, -4) taken in order are the vertices of a rhombus. Find its area. (Hint : Area of rhombus = (1)/(2)xx product of its diagonals)

Area of rhombus is 256 cm^2 . One of the diagonal is half of the other diagonal. The sum of the diagonals is :

Area of rhombus is 60cm^2 , one of its diagonals is 8cm then length of other diagonal is…………cm.

Area of a rhombus =1/2 product of ____________.