`120 g` of an ideal gas of molecular weight `40` is confirmed to a volume of `20 litre at 400 K`, then the pressure of is:

The pressure exerted by 12 g of an ideal gas at temperature t^(@)C in a vessel of volume V litre is 1 atm . When the temperature is increased by 10^(@)C at the same volume, the pressure increases by 10% . Calculate the temperature t and volume V . (Molecular weight of the gas is 120 ).

The pressure exerted by 12 g of an ideal gas at temperature t^@C in a vessel of volume V litre is one atm.when the temperature is increased by 10 degree at the same volume.the pressure increases by 10% calculate the temperature t and volume v.(molecular weight of the gas =120).

The pressure exerted by 12 g of an ideal gas at temperature t^(@)C in a vessel of volume V litre is 1 atm . When the temperature is increased by 10^(@)C at the same volume, the pressure increases by 10% . Calculate the temperature t and volume V . (Molecular weight of the gas is 120 ).

The pressure exerted by 12 g of an ideal gas at temperature t^(@)C in a vessel of volume V litre is 1 atm . When the temperature is increased by 10^(@)C at the same volume, the pressure increases by 10% . Calculate the temperature t and volume V . (Molecular weight of the gas is 120 ).

One mole of an ideal gas at constant temperature 400K is expanded from 10 litre to 20 litre.The work done in the process is

A given quantity of a ideal gas occupies a volume of 100 litres at 100K when the pressure 2 atm. Its temperature is decreased to 50K and its pressure decreases to 1 atm. What is the new volume?