A large sheet carries uniform surface charge density `sigma` . A rod of length 2l has a linear charge density `lamba` on one half and `-lambda` on the second half. The rod is hinged at the midpoint O and makes an angle `theta` with the normal to the sheet. The torque experience by the rod is

A long thin flat sheet has a uniform surface charge density sigma . The magnitude of the electric field at a distance .r. from it is given by

A ring carries a uniform linear charge density on one half and the linear charge density of same magnitude but opposite sign on the other half.

In the figure shown S is a large nonconducting sheet of uniform charge density sigma . A rod R of length l and mass 'm' is parallel to the sheet and hinged at its mid point. The linear charge densities on the upper and lower half of the rod are shown in the figure. Find the angular acceleration of the rod just after it is released.

In the figure shown S is a large nonconducting sheet of uniform charge density sigma . A rod R of length l and mass 'm' is parallel to the sheet and hinged at its mid point. The linear charge densities on the upper and lower half of the rod are shown in the figure. Find the angular acceleration of the rod just after it is released.

In the figure shown S is a large nonconducting sheet of uniform charge density sigma . A rod R of length l and mass 'm' is parallel to the sheet and hinged at its point. The linear charge densities on the upper and lower half of the rod are shown in the figure. Find the angular acceleration of the rod just after it is released [(3sigmalambda)/(2m in_(0))]

A uniform rod AB of mass m and length l is hinged at its mid point C. The left half (AC) of the rod has linear charge density -lamda and the right half (CB) has + lamda where lamda is constant. A large non conducting sheet of uniform surface charge density sigma is also present near the rod. Initially the rod is kept perpendicular to the sheet. The end A of the rod is initialy at a distance d. Now the rod is rotated by a small angle in the plane of the paper and released. Prove that the rod will perform SHM and find its time period.

A uniform rod AB of mass m and length l is hinged at its mid point C. The left half (AC) of the rod has linear charge density -lamda and the right half (CB) has + lamda where lamda is constant. A large non conducting sheet of uniform surface charge density sigma is also present near the rod. Initially the rod is kept perpendicular to the sheet. The end A of the rod is initialy at a distance d. Now the rod is rotated by a small angle in the plane of the paper and released. Prove that the rod will perform SHM and find its time period.