The length of a strip measured with a meter rod is 10.0cm. Its width measured with a venier calipers is 1.00cm. The least count of the meter rod is 0.1 cm and that of vernier calipers 0.01cm. What will be error in its area?

The length of a strip measured with a meter rod is 10.0 cm . Its width measured with a vernier callipers is 1.00 cm . The least count of the meter rod is 0.1 cm and that of vernier callipers is 0.01 cm . What will be the error in its area?

The length of a strip measured with a meter rod is 10.0 cm . Its width measured with a vernier callipers is 1.00 cm . The least count of the meter rod is 0.1 cm and that of vernier callipers is 0.01 cm . What will be the error in its area?

The length of a rectangular plate is measured by a meter scale and is found to be 10.0 cm . Its width is measured by vernier calipers as 1.00 cm . The least count of the meter scale and vernier calipers are 0.1 cm and 0.01 cm respectively. Maximum permissibe error in area measurement is.

The length of a rectangular plate is measured by a meter scale and is found to be 10.0 cm . Its width is measured by vernier callipers as 1.00 cm . The least count of the meter scale and vernier calipers are 0.1 cm and 0.01 cm respectively. Maximum permissibe error in area measurement is.

The length of a rectangular plate is measured by a meter scale and is found to be 10.0 cm . Its width is measured by vernier callipers as 1.00 cm . The least count of the meter scale and vernier calipers are 0.1 cm and 0.01 cm respectively. Maximum permissibe error in area measurement is.

The length of a cylinder is measured with a meter rod having least count 0.1 cm. Its diameter is measured with vernier calipers having least count 0.01 cm. Given that length is 5.0 cm. and radius is 2.0 cm. The percentage error in the calculated value of the volume will be

The length of a cylinder is measured with a meter rod having least count 0.1 cm. Its diameter is measured with vernier calipers having least count 0.01 cm. Given that length is 5.0 cm. and radius is 2.0 cm. The percentage error in the calculated value of the volume will be