A projectile is fired at an angle of `30^(@)` to the horizontal such that the vertical component of its initial velocity is `80m//s`. Its time of fight is `T`. Its velocity at `t=T//4` has a magnitude of nearly.

A projectile is fired at an angle of 30^(@) with the horizontal such that the vertical component of its initial velocity is 80m/s. Find approximatly the velocity of the projectile at time T//4 where T is time of flight.

When a projectile is fired at an angle theta w.r.t horizontal with velocity u, then its vertical component:

A body is projecte at an angle of 60^(@) with the horizontal such that the vertical component of its initial velocity is 40 ms^(-1) . The magnitude of velocity of the projectile at one quarter of its time of flight is nearly, (Acceleration due to gravity, g = 10 ms^(-2))

A Projectile is fired at an angle of 60^(@) to the horizontal with an initial velocity of 800 m / s : Find the time of flight for the projectile toreach its maximum height .

A Projectile is fired at an angle of 60^(@) to the horizontal with an initial velocity of 800 m / s : Find the time of flight of the projectile before it hits the ground .

A projectile is fired with 10ms^-1 at an angle of 60o with horizontal.During its motion,its velocity,when it makes 30o to horizontal is