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If m,n,a gt0;a!=1; loga (m/n)=loga m-log...

If `m,n,a gt0;a!=1; log_a (m/n)=log_a m-log_a n `

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m;n;a>0;a!=1;log_(a)((m)/(n))=log_(a)m-log_(a)n

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Assuming that log (mn) = log m + logn prove that log x^(n) = n log x, n in N

Assuming that log (mn) = log m + logn prove that log x^(n) = n log x, n in N