What will be the value of the verticle components and total intensity of the earth's field ata place where dip is `60^(@)`. Horizontal component is 0.3 G.

What will be the value of vertical component and total intensity of earth field at place where dip is 60^@ . Horizontal component is 0.3G.

Find the value of the vertical component and resultant intensity of the earth's magnetic field at a place where H is 0.2 G and angle of dip is 60°.

Calculate earth's magnetic field at a place where angle of dip delta is 60^(@) and horizontal component of earth's magnetic field is 0.3 G

Calculate earth's magnetic field at a place where angle of dip delta is 60^(@) and horizontal component of earth's magnetic field is 0.3 G

Vertical component of earth's magnetic field at a place is sqrt3 times its horizontal component. If total intensity of earth's magnetic field at the place is 0*4Gauss , find (i) angle of dip (ii) horizontal component of earth's magnetic field.

The elements of earth.s magnetic field at a place are declination, dip and horizontal intensity. The vertical component of earth.s magnetic field at a given place is sqrt 3 times its horizontal component. If total intensity of earth.s magnetic field at the place is 0.4 G find the value of horizontal component of earth.s magnetic field.

At place, the magnitudes of the horizontal component and total intensity of the magnetic field of the earth are 0.3 and 0.6 Oersted respectively. The value of the angle of dip at this place will be