` 3x - y - 5 = 0 , 6x - 2y + k = 0 ( k ne 0 )`

x + y = 5 xy , 3x + 2y = 13 xy ( x ne 0, y ne 0 )

4 x + 6y = 3 xy , 8x + 9 y = 5xy ( x ne 0 , y ne 0 )

The lines x + y + z - 3 = 0 = 2x - y + 5z - 6 and x - y - z + 1 = 0 = 2x + 3y + 7z - k are coplanar then k equals

If the lines 2x + y -3 = 0 , 5x + k y - 3 = 0 and 3x - y - 2 = 0 are concurrent, find the value of k.

x + ( 6) /( y ) = 6, 3x - ( 8)/( y) = 5 ( y ne 0 )

The value of k, so that the following system of equations 3x – y + 5 = 0 and 6x - 2y + k=0 has no solution, is

If the lines 2x + y - 3 = 0 , 5x + ky - 3 = 0 " and " 3x - y - 2 = 0 are concurrent , find the value of k.

If the lines 2x + y - 3 = 0 , 5x + ky - 3 = 0 " and " 3x - y - 2 = 0 are concurrent , find the value of k.

If the lines 2x + y - 3 = 0 , 5x + ky - 3 = 0 " and " 3x - y - 2 = 0 are concurrent , find the value of k.