The equation of the normal to the ellipse `x^(2)/4+y^(2)/1=1` at (2, -1) is

The equation of the normal to the ellipse (x^(2))/(4)+(y^(2))/(2)=1 at the point whose eccentric angle is (pi)/(4) is

The equation of the normal to the ellipse (x^(2))/(10)+(y^(2))/(5)=1 at (sqrt(8), 1) is

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

Find the equation of the normal to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the positive end of the latus rectum.

The equation of the normal to the curve x^(2)=4y at (1,2) is

Find the equation of normal to the ellipse x^(2)+4y^(2)=4 at (2 cos theta, sin theta) . Hence find the equation of normal to this ellipse which is paralel to the line 8x+3y=0 .

Equation of normal to the ellipse at (x_(1);y_(1))

Find the equation of the normal to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at the positive end of the latus rectum.