For `NaCI`, lattice energy ` = - 186 kcal//mol`, the solvation energy of `Na^(+) and CI` are `-97 and -85 kcal//"mole"` respectively. Therefore for `NaCI (s)`

For NaCl , lattice energy = - 186 kcal//mol , the solvation energy of Na^(+) and Cl are -97 and -85 kcal//"mole" respectively. Therefore for NaCl (s)

The ionisation energy for 'Sc', 'Y' and 'La' are x,y and z kcal/mol respectively. Choose the correct relationship between them.

Calculate the lattice energy of NaCI crystal from the following data by the use of Born-Haber cycle. Sublimation energy of Na = 26 kcal//g atom, dissociation energy of CI_(2) = 54 kcal//"mole" , ionisation energy of Na(g) = 117 kcal//"mol" , electron affinity for CI(g) = 84 kcal//g atom, heat of formation of NaCI =- 99 kcal//"mole" .

Calculate the enthalpy of solution of sodium chloride. The lattice energy of NaCl is +186 kcal mol^(-1) . And the solution enthalpies of cations and anions are respectively -97 and -85 kcal mol^(-1)