The displacement from mean position of a particle in SHM at 3 seconds is `sqrt(3)` /2 of the amplitude. Its time period will be :

The displacement (from intial position) of a particle executing SHM with amplitude A in half the time period is always

The shortest distance travelled by a particle executing SHM form mean position in 2 seconds is equal to ( sqrt(3))/(2 ) times of its amplitude . Determine its time period .

The following graph shows the displacement of the bob from its mean position versus time . The time period and the amplitude of the bob are :

The acceleration of a particle performing S.H.M. is 12 cm/ s^(2) at a distance of 3 cm from the mean position. Its time period is _____ .

The shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to (sqrt(3)//2) times its amplitude. Determine its time period.

The shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to (sqrt(3)//2) times its amplitude. Determine its time period.

The shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to (sqrt(3)//2) times its amplitude. Determine its time period.

A particle executies linear simple harmonic motion with an amplitude 3cm .When the particle is at 2cm from the mean position , the magnitude of its velocity is equal to that of acceleration .The its time period in seconds is

A particle executies linear simple harmonic motion with an amplitude 3cm .When the particle is at 2cm from the mean position , the magnitude of its velocity is equal to that of acceleration .The its time period in seconds is

The acceleration of a particle performing SHM is 12cm//s^2 at a distance of 3 cm from the mean position. Calculate its time-period.