A body is projected at time `t = 0` from a certain point on a planet's surface with a certain velocity at a certain angle with the planet's surface (assumed horizontal). The horizontal and vertical displacement x and y (in metre) respectively vary with time t in second as, `x= (10sqrt(3)) t and y= 10t - t^2`. The maximum height attained by the body is

A body is projected at time t = 0 from a certain point on a planet’s surface with a certain velocity at a certain angle with the planet’s surface (assumed horizontal). The horizontal and vertical displacements x and y (in meters) respectively vary with time t (in second) as x= 10 sqrt3t , y= 10t -t^2 What is the magnitude and direction of the velocity with which the body is projected ?

A body is projected at time t = 0 from a certain point on a planet’s surface with a certain velocity at a certain angle with the planet’s surface (assumed horizontal). The horizontal and vertical displacements x and y (in meters) respectively vary with time t (in second) as x= 10 sqrt3t , y= 10t -t^2 What is the magnitude and direction of the velocity with which the body is projected ?

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x= 6 "t" and y= 8t -5t^2 meter.The range of the projectile in metre is:

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x= 6 "t" and y= 8t -5t^2 meter.The range of the projectile in metre is:

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x = 6t metre and y = 8t-5t^2 metre. The range of the projectile in metre is