चित्र में DE||BC और AD:DB = 5:4 है तो `(ar(DeltaDEF))/(ar(DeltaCFB))` ज्ञात कीजिये

In the given figure DE||BC and AD:DB =5:4 Find the ratio ar (Delta DEF) : ar (Delta CFB)

In the given figure DE||BC and AD:DB =5:4 Find the ratio ar (Delta DEF) : ar (Delta CFB)

In Fig. 7 .85, DEabs()BC and AD : DB = 5 : 4. Find ("Area"(DeltaDEF))/("Area"(DeltaCFB))

In the given figure, DE//BC and AD:DB=5:4, then (DeltaDEF)/(DeltaCFB) =

In the given figure, DE||BC . If DE : BC = 3 : 5 , find (ar(ADE))/(ar(BCED)) .

In DeltaABC , D and E are points on AB and AC respectively such that DE is parallel to BC. If AD= 2 cm, BD = 3 cm, then (ar(DeltaADE))/(ar(DeltaABC)) is

In triangle ABC ,AD is a median and P is a point on AD such that AP : PD = 3 : 4. Then ar (triangle BPD): ar (triangle ABC) is equal to: त्रिभुज ABC में, AD एक माध्यिका है और P, AB पर स्थित ऐसा बिंदु है कि AP : PD = 3 : 4 है| ar (triangle BPD): ar (triangle ABC) ज्ञात करें |

In the given figure, DE // BC. Given that AD = 1/2 BD , calculate DE, if BC = 45 cm. Also , find (Ar. (Delta ADE))/(Ar. (DeltaABC)) and (Ar.(DeltaADE))/(Ar.("trapezium BCED"))

In the given figure DE || BC . If AD = 1.5 cm , BD = 2AD , then find (ar(Delta "ADE"))/(ar("trapezium BCED"))

In the given figure, DE is parallel to the base BC of triangle ABC and AD: DB = 5: 4. Find the ratio : ("Area of "DeltaDEF)/("Area of"Delta BFC)