A solid cylinder rolls down from an inclined plane of height h. What is the velocity of the cylinder when it reaches at the bottom of the plane ?

A solid cylinder of mass M and radius R rolls down an inclined plane of height h. The angular velocity of the cylinder when it reaches the bottom of the plane will be :

A solid cylinder of mass M and radius R rolls down an inclined plane of height h. The angular velocity of the cylinder when it reaches the bottom of the plane will be :

A solid cylinder of mass M and radius R rolls down an inclined plane of height h. The angular velocity of the cylinder when it reaches the bottom of the plane will be :

If a solid cylinder rolls down an inclined plane, then its:

If a solid cylinder rolls down an inclined plane, then its:

Assertion: A solid cylinder of mass m and radius r rolls down an inclined plane of height H. The rotational kinetic energy of the cylinder when it reaches the bottom of the plane is mgH/3. Reason: The total energy of the cylinder remains constant throughout its motion.

A solid cylinder of radius r rolls down an inclined plane of height h and inclination theta . Calculate its speed at the bottom of the plane using energy method. Also calculate the time taken to reach of the bottom.

A solid cylinder rolls down an inclined plane of height h and inclination theta . Calculate its speed to the bottom of the plane using acceleration method and energy method. Also calculate the time taken to reach of the bottom.

A solid cylinder of mass 0.1 kg having radius 0.2 m rolls down an inclined plane of height 0.6 m without slipping. The linear velocity of the cylinder at the bottom of the inclined plane is