The shortest distance between the two lines `L_1:x=k_1, y=k_2 and L_2: x=k_3, y=k_4` is equal to

The shortest distance between the lines L_(1) : (x+1)/3 = (y+2)/1 =(z+1)/2 L_(2) = (x-2)/1 = (y+2)/2 = (z-3)/3 is

The shortest distance between the line L_1=(hat i - hat j hat k) lambda (2 hat i - 14 hat j 5 hat k) and L_2=(hat j hat k) mu (-2 hat i - 4 hat 7 hat) then L_1 and L_2 is

Find the shortest distance between the lines l_(1) and l_(2) given by (x-1)/-1=y/3=(z-2)/2 and x/2 =(y-1)/-6=z/-4

Find the shortest distance between the lines l_(1) and l_(2) given by (x-1)/-1=y/3=(z-2)/2 and x/2 =(y-1)/-6=z/-4

The shortest distance between lines L_(1):(x+1)/(3)=(y+2)/(1)=(z+1)/(2) , L_(2):(x-2)/(1)=(y+2)/(2)=(z-3)/(3) is

The shortest distance between lines L_(1):(x+1)/(3)=(y+2)/(1)=(z+1)/(2) , L_(2):(x-2)/(1)=(y+2)/(2)=(z-3)/(3) is

If the shortest distance between the lines (x-1)/(1)=(y-1)/(1)=(z-1)/(1) and (x-2)/(1)=(y-3)/(1)=(z-4)/(1) is equal to sqrt(K) unit, then the value of K is -

The distance between the lines given by (x-2y)^(2)+k(x-2y)=0 is 3, then k=

If the lines x-y-1=0,4 x+3 y=k and 2 x-3 y+1=0 are concurrent then k=

If the distance between the palens 2x- y + 2z = 1 and 4x-2y + 4z = k is 1/6 then k = ...............