The electric field at point (30, 30, 0) due to a charge `0.008muC` at origin will be (coordinates are in cm)

The electric field at (30, 30) cm due to a charge of -8nC at the origin in NC^(-1) is

The electric field at (30,30) cm due to a charge of - 8 nC at the origin in NC^(-1) is

Electric field due to point charge

Find out electric field intensity at point A (0, 1m, 2m) due to a point charge -20 muC situated at point B (sqrt(2)m, 0, 1m) .

Find out electric field intensity at point A (0, 1m, 2m) due to a point charge -20 muC situated at point B (sqrt(2)m, 0, 1m) .

The electric field at a point due to a point charge is 60 N//C and the electric potential at that point is 30 J//C . Calculate the distance of the point from the charge and the magnitude of the charge.

The electric field at a point due to a point a charge is 30 N//C , and the electric potential at that point is 15 J//C . Calcualte the distance of the point from the charge and the magnitude of the charge.

find the electric field strength due to a point charge of 5 muC at a distance of 80 cm from the charge.