In a Young's double slit experiment if the slit separation is twice the wavelength of light used then the maximum number of interference maxima is

In Young's double slit experiment if the distance between two slits is equal to the wavelength of used light. Then the maximum number of bright fringes obtained on the screen will be ......

In Young's double slit experiment, if the distance between two slits is equal to the wavelength of used light. Then the maximum number of bright firnges obtained on the screen will be

In Young's double slit experiment, if the distance between two slits is equal to the wavelength of used light. Then the maximum number of bright firnges obtained on the screen will be

In Young's double slit experiment, if th distance between two slits is double of the wavelength of light used. Prove that maximum 5 bright fringes will be obtained on the screen.

In Young's double slit experiment, the interference bright fringes are of:

In Young's double slit experiment with slit separation d, a monochromatic light of wavelength lamda is used. The angular separation of the fringes is

In Young's double slit interference experiment, the slit separation is made 3 fold. The fringe width becomes

In Young’s double slit experiment, first dark fringe occurs directly opposite to slit. Wavelength of light used is