Longitudinal stress of `1 kg//mm^(2)` is applied on a wire. The percentage increase in length is `(Y = 10^(11) N//m^(2))`

Longitudinal stress of 1" kg/mm"^(2) is applied on a wire. The percentage increase in length is (Y=10''" N/m"^(2))

A stress of 1kg//mm^(2) is applied on a wire. If the modulus of elasticity of the wire is 10^(10) "dyne"//cm^(2) , then the percentage increase in the length of the wire will be

A stress of 1 kg mm^(-2) is applied to a wire of which Young's modulus is 10^(11) Nm^(-2) and 1.1xx10^(11) Nm^(-2) . Find the percentage increase in length.

A uniform cylindrical wire is subjected to a longitudinal tensile stress of 5 xx 10^(7) N//m^(2) . Young's modulus of the material of the wire is 2 xx 10^(11) N//m^(2) . The volume change in the wire is 0.02% . The factional change in the radius is

A uniform cylindrical wire is subjected to a longitudinal tensile stress of 5 xx 10^(7) N//m^(2) . Young's modulus of the material of the wire is 2 xx 10^(11) N//m^(2) . The volume change in the wire is 0.02% . The factional change in the radius is

A stress of 1 kg wt//mm^(2) is applied to a wire whose Young's modulus is 10^(12)"dyne"//cm^(2) . The percentage increase in its length is

A stress of 1kg//mm^2 is applied on a wire. If the modulus of elasticity of the wire is 10^10 dyne/ cm^2 , then the percentage increase in the length of the wire will be

What should be the weight suspended from the end of a steel wire 2 m in length and w mm in diameter to increase the length by 1 mm ? (Y=19xx10^(11)N//m^(2))