Calculate the temperature at which the rms speed of nitrogen molecules will be equal to `8 km//s`. Given molecuar weight of nitrogen = 28 and `R = 8.31 J//mole//K.

Calculate the temperature at which the rms velocity of oxygen molecules will be 2 km//s-R = 8.31 J m^(-1) K^(-1) .

Compute the temperature at which the r.m.s speed of nitrogen molecules is 832m//s . [Universal gas constant, R=8320J//k mole K , molecular weight of nitrogen =28 .]

Calculate the temperature at which the rms velocity of hydrogen will be equal to 8 km//s. Take R = 8.31 J "mole"^(-1) K^(-1)

The temperature at which rms velocities of nitrogen gas molecules will be doulbed that at 0^(@)C is

The temperature at which the rms velocity of oxygen molecules equals to that of nitrogen molecules at 0^(@)C is

Find rms speed of Nitrogen molecules at temperature 27^(@)C .

Find the KE per kg of nitrogen molecule at 127^@C (molecular weight of nitrogen = 28, R = 8320 J//K mole K ).

The temperature at which the r.m.s. velocity of oxygen molecules equal that of nitrogen molecules at 100^(@)C is nearly.