In a series LCR circuit, an alternating emf (V) and current (I) are given by the equation `V =V_0sinomegat,I=I_0sin(omegat+pi/3)` The average power dissipated in the circuit over a cycle of AC is

In a series LCR circuit , and alternating emf (v) and current (i) are given by the equation v=v_(0) sin omegat, i=i_(0)sin (omegat+(pi)/(3)) . The average power dissipated in the circuit over a cycle of AC is

In a series L.C.R. circuit alternating emf (v) and current (i) are given by the equation v=v_(0) sin omega t , i=i_(0)sin(omega t+(pi)/(3)) The average power dissipated in the circuit over a cycle of AC is

In LCR series circuit , an alternating emf e and current i are given by the equations e = sin (100 t) volt . i=100 sin (100 t + (pi)/(3)) mA The average power dissipated in the circuit will be

In LCR series circuit, an alternating e.m.f. 'e' and current 'I' are given by the equations e=100sin(100t) volt and I=100sin(100t+(pi)/(3))mA The average power dissipated in the circuit will be

In any AC circuit the emf (e) and the current (i) at any instant are given respectively by e= V_(0)sin omega t i=I_(0) sin (omegat-phi) The average power in the circuit over one cycle of AC is

In any AC circuit the emf (e) and the current (i) at any instant are given respectively by e= E_(0)sin omega t i=I_(0) sin (omegat-phi) The average power in the circuit over one cycle of AC is

In an a.c. circuit the e.m.f. € and the current (i) al any instant are-given respectively by e = E_(0)sin omegat I = l_(0)sin (omegat-phi) The average power in the circuit over one cycle of a.c. is

Voltage V and current I in AC circuit are given by V =50sin(50 t)volt,I = 50 sin ( 50t+(pi)/(3) )mA The power dissipated in the ciruit is