If `tan alpha = 1/3` and `tan beta = 1/2`, then: `tan(alpha + beta)`=

If tan (alpha + beta) = 2 and tan (alpha - beta) = 1, then tan (2 alpha ) is equal to:

If" " n tan alpha = (n+1) tan beta " then show that", tan (alpha - beta) = (sin 2 beta)/(2n + 1 - cos2 beta).

If sin (alpha+beta)=1, sin (alpha-beta)=1/2 , then tan (alpha+ 2beta). tan (2 alpha+beta) is equal to :

If sin(alpha + beta) = 1 , sin(alpha - beta) = 1/2 , then : tan(alpha + 2beta)tan(2alpha + beta) is equal to :

If tan beta =(n tan alpha )/(1+(1-n) tan^(2) alpha ) , then tan(alpha-beta)=

If 2tan alpha=3tan beta then tan(alpha-beta)=

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =

If tan alpha=(1-cos beta)/(sin beta), then a )tan3 alpha=tan2 beta(b)tan2 alpha=tan beta(c)tan2 beta=tan alpha(d) none of these

If tan(2alpha+beta)=x & tan(alpha+2beta)=y , then [ tan3(alpha+beta)]. [ tan(alpha-beta)] is equal to (wherever defined)