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H(2)(g) + Cl(2) rarr 2HCl (g), Delta H =...

`H_(2)(g) + Cl_(2) rarr 2HCl (g), Delta H = -44K.cals 2 Na(s)+2HCl (g)rarr 2NaCl(s)+H_(2)(g), Delta H = -152K.cal`
`Na(s)+(1)/(2)Cl_(2)(g) rarr NaCl(s), Delta H = ?`

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If, H_(2)(g)+Cl_(2)(g)rarr 2HCl(g) , Delta H^(@)=-44 Kcal 2Na(s)+2HCl(g)rarr 2NaCl(s)+H_(2)(g), Delta H=-152 Kcal Then, Na(s)+0.5Cl_(2)(g)rarr NaCl(s) , Delta H^(@) = ?

If, H_(2)(g)+Cl_(2)(g)rarr 2HCl(g) , Delta H^(@)=-44 Kcal 2Na(s)+2HCl(g)rarr 2NaCl(s)+H_(2)(g), Delta H=-152 Kcal Then, Na(s)+0.5Cl_(2)(g)rarr NaCl(s) , Delta H^(@) = ?

If H_2(g)+Cl_2(g)→ 2HCl , ^@=-44 kcal 2Na(s)+2HCl(g→ )2NaCl(s)+H_2(g), △ H =-152 kcal then, Na(s)+0.5Cl_2(g)→ NaCl(s),△ H =?

Given : (i) NH_(3) (g) + 3Cl_(2)(g) rarr NCl_(3)(g)+3HCl(g) , Delta H_(1) (ii) N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g) , Delta H_(2) (iii) H_(2)(g)+Cl_(2)(g) rarr2HCl(g) , Delta H_(3) Express the enthalpy of formation of NCl_(3)(g)(Delta H_(f)) in terms of DeltaH_(1), Delta H_(2) and Delta H_(3) :

NH_(3)(g) + 3Cl_(2)(g) rarr NCl_(3)(g) + 3HCl(g), " "DeltaH_(1) N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g), " "Delta H_(2) H_(2)(g) + Cl_(2)(g) rarr 2HCl(g), " "Delta H_(3) The heat of formation of NCl3(g) in the terms of DeltaH_(1), DeltaH_2 and DeltaH_(3) is :

NH_(3)(g) + 3Cl_(2)(g) rarr NCl_(3)(g) + 3HCl(g), " "DeltaH_(1) N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g), " "Delta H_(2) H_(2)(g) + Cl_(2)(g) rarr 2HCl(g), " "Delta H_(3) The heat of formation of NCl3(g) in the terms of DeltaH_(1), DeltaH_2 and DeltaH_(3) is :

Calculate in kJ for the following reaction : C(g) + O_(2)(g) rarr CO_(2)(g) Given that, H_(2)O(g) + C(g) + H_(2)(g) , Delta H = +131 kJ CO(g) + 1/2 O_(2)(g) rarr CO_(2)(g), " " Delta H = -242 kJ H_(2)(g) + 1/2 O_(2)(g) rarr H_(2)O(g), " "DeltaH = -242 kJ

Calculate in kJ for the following reaction : C(g) + O_(2)(g) rarr CO_(2)(g) Given that, H_(2)O(g) + C(g) + H_(2)(g) , Delta H = +131 kJ CO(g) + 1/2 O_(2)(g) rarr CO_(2)(g), " " Delta H = -242 kJ H_(2)(g) + 1/2 O_(2)(g) rarr H_(2)O(g), " "DeltaH = -242 kJ

Given the following equations and values, determine the enthalpy of reaction at 298 K for reaction: C_(2)H_(4)(g) + 6F_(2)(g) rarr 2CF_(4)(g) + 4HF(g) H_(2)(g) + F_(2)(g) rarr 2HF(g) " "Delta H_(1)^(@) = -537 kJ C(s) + 2F_(2)(g) rarr CF_(4)(g) " "DeltaH_(2)^(@) = -680 kJ 2C(s) + 2H_(2)(g) rarr C_(2)H_(4)(g) " "Delta H_(3)^(@) =52 kJ