A particle exectues a linear S.H.M. of amplitude 2 cm. When it is at 1cm from the mean position, the magnitudes of its velocity and acceleration are equal. What is its maximum velocity ? `[sqrt(3)=1.732]`

A particle performs a S.H.M. of period 2pi sec and amplitude 2 cm. At what dis"tan"ce from the mean position, its velocity and acceleration are numerically equal ?

When a particle executing a linear S.H.M. moves from its extreme position to the mean position, its

When a particle executing a linear S.H.M. moves from its extreme position to the mean position, its

A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is