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lines L1:ax+by+c=0 and L2:lx+my+n=0 inte...

lines `L_1:ax+by+c=0` and `L_2:lx+my+n=0` intersect at the point `P` and make a angle `theta` between each other. find the equation of a line `L`different from `L_2` which passes through `P` and makes the same angle `theta` with `L_1`

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let the equation be `alx+bly+cl=0` (i)and`alx+amy+an=0 (ii)`
on solving simultaneously
`y=(an-cl)/(bl-am)` putting y in (i) we will get, `x=(cm-bm)/(bl-am)` so the point of intersection is
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