The equation of S.H.M. of a particle is `a+4pi^(2)x=0`, where a is instantaneous linear acceleration at displacement x. Then the frequency of motion is

The equation of motion of a particle in SHM is a +16 pi^(2)x = 0 . Here 'a' is linear acceleration of the particle at displacement x (a,x are in SI) . Its time period is

The equation of motion of a particle in SHM is a +4x = 0 . Here 'a' is linear acceleration of the particle at displacement 'x' in metre. Its time period is

The equation of motion of a particle executing S.H.M. is a = - bx , where a is the acceleration of the particle, x is the displacement from the mean position and b is a constant. What is the time period of the particle ?

The graph between instantaneous acceleration and angualr displacement of a particle performing S.H.M. is

Write the relation between acceleration, displacement and frequency of a particle executing S.H.M.

The equation motion of a particle in S.H.M. is a + 16 p^(2)x = 0 . In the equation .a. is the linear acceleration (in m//sec^(2) ) of the particle at a displacement .x. in meter. The time period of S H M in seconds is