If solution containing `0.15 g` of solute dissolved in `15 g` of solvent boils at a temperature higher by `0.216^(@)C` than that of pure solvent, the molecular mass of the substance is `(K_(b)=2.16^(@)C)`

0.15g of a substance dissolved in 15g of a solvent boiled at a temp. higher by 0.216^(@)C than that of the pure solvent. Find out the molecular weight of the substance (K_(b) for solvent is 2.16^(@)C )

0.15 g of a substance dissolved in 15 g of a solvent boiled at a temp. higher by 0.216^@C then that of the pure solvent. The molecular weight of the substance is ( K_b for solvent is 2. 16^@C .)

0.25 g of a substance dissolved in 25 g of solvent boiled at a temperature higher by 0.208^@C than that of the pure solvent. What is the molercular mass of the substance. [K_(b)" for solvent =2.16 K kg/mol or Km"^(-1)]

0.15 g of a substance dissolved in 15 g of solvent boiled at a temperature higher at 0.216^(@) than that of the pure solvent. Calculate the molecular weight of the substance. Molal elevation constant for the solvent is 2.16^(@)C

0.15 g of a subatance dissolved in 15 g of solvent boiled at a temperature higher at 0.216^(@) than that of the pure solvent. Calculate the molecular weight of the substance. Molal elecation constant for the solvent is 2.16^(@)C

0.15 g of a subatance dissolved in 15 g of solvent boiled at a temperature higher at 0.216^(@) than that of the pure solvent. Calculate the molecular weight of the substance. Molal elecation constant for the solvent is 2.16^(@)C

The boiling point of a solution containing 2.62 g of a substance A in 100 g of water is higher by 0.0512^(@)C than the boiling point of pure water. The molar mass of the substance ( K_(b)=5.12Km^(-1) ) is :