The displacement of a particle in S.H.M. is given by `x=5["cos" pi t + "sin" pi t]` where x is in metre. The amplitude of motion of the particle is given by

The displacement of a particle executing a S.H.M. is given by x= A "sin" omega t +A "cos" omega t . What is the amplitude of motion ?

The displacement of a particle making S.H.M. is given by x=6cos(100t+(pi)/(4))m then the frequency is

The displacement of a particle performing a S.H.M. is given by x=0.5 "sin" 100 pi (t + 0.05) , where x is in metres and t is in second. Its periodic time in second is

The displacement of a particle in S.H.M. varies according to the relation x= 4 (cos pi t +sin pi t ) . The amplitude of the particle is

The displacement of a particle in S.H.M. is given by x= B "sin" (omega t + alpha) . The initial position (at time t=0), of the particle is the initial phase angle if the angular frequency of the particle is pi rad//s ?

The displacement of a particle executing S.H.M is given by x= 0.01 sin 100pi (t + 0.05) . The time period is

The displacement of a particle performing a S.H.M. is given by x =12 "cos" (omega t + alpha) cm . If at time t, the displacement of the particle is 6 cm, them the phase of the particle at that instant is

The displacement of a particle performing S.H.M. is given by x=10 "sin"(omega t+ alpha) metre. If the displacement of the particle is 5m, then the phase of S.H.M. is