A particle executes a S.H.M. of amplitude 4 cm and period 4 sec. If at time t=0, the net force acting on the particle is zero, then its velocity at that point is given by

A particle executes a linear S.H.M. of amplitude 8 cm and period 2s. The magnitude of its maximum velocity is

A particle executes S.H.M. of amplitude 25 cm and time period 3 s. What is the minimum time required for the particle to move between two points 12.5 cm on either side of the mean position ?

A particle executes a S.H.M. of amplitude 20 cm and period 3 s. What is the minimum time required by the particle to move between two points 10 cm on eith side of the mean position ?

particle is executing S.H.M. If its amplitude is 2 m and periodic time 2 seconds , then the maximum velocity of the particle will be

A particle executing SHM of amplitude 4 cm and T=4 s .The time taken by it to move from position to half the amplitude is

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the acceleration of the particle at a distance 5 cm from the equilibrium position.

A particle is executing S.H.M. of amplitude 5 cm and period of 2 s. Find the speed of the particle at a point where its acceleration is half of its maximum value.

A particle executing simple harmonic motion has amplitude of 1 m and time period 2 s . At t = 0 , net force on the particle is zero. Find the equation of displacement of the particle.

A particle excuting S.H.M. of amplitude 4 cm and T = 4 sec .The time take by it to move position extreme position to half the amplitude is

A particle executes S.H.M with amplitude of 10 cm and period of 10 s. Find the velocity of the particle at a distance 5 cm from the equilibrium position.