The line `(x-2)/3 = (y-3)/4 = (z-4)/5` is parallel to the plane

The line (x-2)/(3)=(y-3)/(4)=(z-4)/(5) is is parallel to the plane

Find the distance of the point (-2,3,-4) from the line (x+2)/3=(2y+3)/4=(3z+4)/5 measured parallel to the plane 4"x"+12"y"-3"z"+1=0.

Find the distance of the point (-2, 3, 4) from the line (x+2)/3=(2y+3)/4=(3z+4)/5 measured parallel to the plane 4x+12y-3z+1=0 .

Distance of point P(-2,3,4) from the line (x+2)/3=(2y+3)/4=(3z+4)/5 measured parallel to the plane 8x+6y-9z+1=0 is

Distance of point P(-2,3,4) from the line (x+2)/3=(2y+3)/4=(3z+4)/5 measured parallel to the plane 8x+6y-9z+1=0 is

If the line (x+1)/3=(y-2)/4=(z+6)/5 is parallel to the planes 2x-3y+kz=0 , then the value of k is

The sine of the angle between the line (x-2)/(3) = (y-3)/(4) = (z-4)/(5) and the plane 2x-2y+z=5 is

Which one of the following is the plane containing the line (x-2)/2=(y-3)/3=(z-4)/5 and parallel to z-axis?

The distance of the point P(-2, 3, -4) from the line (x+2)/(3)=(2y+3)/(4)=(3z+4)/(5) measured parallel to the plane 4x+12y-3z+1=0 is d, then find the value of (2d-8), is……..