The vibrations of a string of length 60 cm fixed at both the ends are represented by the equation ` y = 2 "sin"((4pix)/(15)) "cos" (96 pit)` where x and y are in cm. The maximum number of loops that can be formed in it is

The vibrations of a string of length 600cm fixed at both ends are represented by the equation y=4 sin (pi (x)/(15)) cos (96 pi t ) where x and y are in cm and t in seconds.

The vibrations of a string of length 60 cm fixed at both ends are represented by the equation y=4 sin (pix//15) cos (96 pit) where x and y are in cm and t in seconds. The maximum displacement at x = 5 cm is–

The vibrations of string of length 60 cm fixed at both ends are presented by the equations y = 4 sin ( pi x//15) cos ( 96 pi t) where x and y are in cm and t in s . The maximum displacement at x = 5 cm is

The vibrations of a string of length 60 cm fixed at both ends are represented by the equation y=4sin((pix)/15) cos (96 pi t) , where x and y are in cm and t in seconds. (a)What is the maximum displacement of a point at x = 5cm ? (b)Where are the nodes located along the string? (c)What is the velocity of the particle at x=7.5cm and t=0.25s? (d)Write down the equations of the component waves whose superposition gives the above wave.

The vibrations of a string of length 60 cm fixed at both ends are represented by the equation y=4sin((pix)/15) cos (96 pi t) , where x and y are in cm and t in seconds. (a)What is the maximum displacement of a point at x = 5cm ? (b)Where are the nodes located along the string? (c)What is the velocity of the particle at x=7.5cm and t=0.25s? (d)Write down the equations of the component waves whose superposition gives the above wave.