The optical path difference between the two light waves arriving at a point on the screen is

The optical path difference between two identical light waves arriving at a point (P) on the screen is 27xx10^(-7)m . For P to be a dark point, the wavelength of light used should be

The optical path difference between two light waves arriving at a point simultaneously is 260 (lamda)/4 . The point is

The optical path difference between to light waves arriving at a point simultaneously is 130 (lamda)/2 , if the path difference is 650xx10^(-5) cm, then the wavelength of light will be

The optical path difference between the two identical waves arriving at a point is 0.05 cm. If wavelength of light uses is 5000Å , then the number of dark fringes passing through that point will be

In a biprism experiment, the optical path difference between the two identical waves arriving at a point is 0.05 cm. if the wavelength of light used of 5000 Å, then the number of dark friges passing through that point will be

The optical path difference between the two indentical waves arriving at a point is 75.5 lambda . Is the point bright or dark ?

The path difference between two interfering light waves meeting at a point on the screen is ((87)/(2))lamda . The band obtained at that point is

The optical path difference between two identical light waves arriving at a point is 31.5 lamda , where lamda is the wavelength of light. The point is

The optical path difference between two identical waves arriving at a point is 371 lambda . Is the point bright or dark ? If the path difference is 0.24 mm . Calculate the wavelength of light used .