A reflecting surface is represented by the equation
`y = (2L)/(pi) sin ((pi x)/(L))`, where `0 le x le L`. A ray of light travelling horizontally becomes vertical after reflection with the surface. The co-ordinates of the point where this ray is incident is.

The reflecting surface is represented by the equation 2x =y^2 as shown in the figure. A ray travelling horizontal becomes vertical after reflection. The co-ordinates of the point of incidence are

A refracting surface is represented by the equation x^(2)+y^(2) = a^(2) . A ray travelling in negative x-directed towards positive y-direction after reflection from the surface at point P. Then co-ordinates of point P are

A refracting surface is represented by the equation x^(2)+y^(2) = a^(2) . A ray travelling in negative x-directed towards positive y-direction after reflection from the surface at point P. Then co-ordinates of point P are

The cross-section of a reflecting surface is represented by the equation x^2 + y^2 = R^2 as shown in the figure. A ray travelling in the positive x direction is directed toward positive y direction after reflection from the surface at point M. The coordinate of the point Mon the reflecting surface is

Find sin 2x if cos x=sqrt3/2 where 0 le x le pi/2

Find sin 2x if cos x=1/sqrt2 where 0 le x le pi/2

If the equation of mirror is given by y= 2//pi "sin"pix (y gt 0 , 0 le x le 1 ) then find the point on which horizontal ray should be incident so that the reflected ray become perpendicular to the incident ray

If the equation of mirror is given by y= 2//pi "sin"pix (y gt 0 , 0 le x le 1 ) then find the point on which horizontal ray should be incident so that the reflected ray become perpendicular to the incident ray