If the point P on the curve `4x^2+5y^2-20=0` is farthest from the point `Q(0,-4)` than Find `PQ^2`.

The point on the curve 4x^2+a^2y^2=4a^2 ; 4lta^2lt8 that is farthest from the point (0,-2) is

The point on the curve 4x^2+a^2y^2=4a^2 ; 4lta^2lt8 that is farthest from the point (0,-2) is

Find the point on the curve 4x^2 + a2y^2 = 4a^2, 4 < a^2 < 8 that is farthest from the point (0,-2)

The point on the curve 4x^(2)+a^(2)y^(2)=4a^(2)4

Find the co-ordinate of the point on the circle x^(2)+y^(2)-12x-4y+30=0, which is farthest from the origin.

Find the co-ordinate of the point on the circle x^2+y^2-12x-4y +30=0 , which is farthest from the origin.

Find the point on the curve 4x^2+a^2y^(2)=4a^(2), 4 lt a^(2) lt 8 that is farthest from the point (0, –2).

Find the point on the curve 4x^(2)+a^(2)y^(2)=4a^(2),4 lt a^(2) lt 8 that is farthest from the point (0,-2) .

If Q is the point on the parabola y ^(2) =4x that is nearest to the point P (2,0) then PQ =