In a `DeltaABC`, a line is drawn passing through centroid dividing AB internaly in ratio 2:1 and AC in `lamda:1` (internally). The value of `lamda` is

In DeltaABC , P is the mid point of BC,Q divides CA internally in the ratio 2:1 and R divides AB externally in the ratio 1:2 then

In DeltaABC , P is the mid point of BC,Q divides CA internally in the ratio 2:1 and R divides AB externally in the ratio 1:2 then

Find the equation of the straight line passing through the origin and dividing the segment of the straight line passing through the (4,-2) and (1,10) internally in the ratio 2:1 .

Find the equation of the line which passes through the point (5-1), and divides the join of the points (9,2) and (3,4) internally in the ratio 1:2 .

A circle passes through the points of intersection of the lines lamda x-y+1=0 and x-2y+3=0 with the coordinates axes. Show that lamda=2 .

A circle passes through the points of intersection of the lines lamda x-y+1=0 and x-2y+3=0 with the coordinates axes. Show that lamda=2 .

(-1,lamda,-3) is the coordinate of centroid of the triangle formed by the points (3,2,-5),(-3,8,-5) and (-3,2,1) . Then the value of lamda is

A line passing through the point (1,1,1) from a tiangle of area sqrt(6) sq. unit with the lines x=y=z and x=(y)/(2)=(z)/(3) . If the point of intersection of the line with the second line be (lamda,2lamda,3lamda) , then the value of lamda is -