Solubility of Zirconium phosphate `Zr_3(PO_4)_4` is 's' moles per litre. Solubility product of `K_(sp)` may be given as

The solubility of Ca_(3)(PO_(4))_(2) in water is y moles // litre. Its solubility product is

The solubility of Ca_(3)(PO_(4))_(2) in water is y moles // litre. Its solubility product is

The solubility of CaF_2 in water is 's' moles per litre, its solubility product is

The solubility of the salt M_(m) A_(n) in water is 's' moles per litre. The solubility product of the salt is (at constant temperature)

At a certain temperature, the solubility of the salt M_(m)A_(n) in water is s moles per litre. The solubility product of the salt is :

The solubility of Al(OH)_3 is 's' mol per litre, the solubility product of Al(OH)_ 3 is :

Zirconium phosphate [Zr_3(PO_4)_4] dissociates into three zirconium cations of charge +4 and four phosphate anions of charge -3 . If molar solubility of zirconium phosphate is denoted by S and its solubility product by K_(sp) then which of the following relationship between S and K_(sp) is correct ?

Zirconium phosphate [Zr_3(PO_4)_4] dissociates into three zirconium cations of charge +4 and four phosphate anions of charge -3 . If molar solubility of zirconium phosphate is denoted by S and its solubility product by K_(sp) then which of the following relationship between S and K_(sp) is correct ?

If the solubility of Pb3 (PO_4)_2 is mol per litre, then the solubility product of Pb_3(PO_4)_2 will be :