The area of the rectangle formed by the perpendicular from centre of `x^2/9+y^2/4=1,` to the tangents area normal the point where occeses angle is `pi/4` equals

The area of the rectangle formed by the perpendiculars from the centre of the ellipse (x^(2))/(9)+(y^(2))/(4)=1 to the tangent and normal at the point whose eccentric angle is (pi)/(4) , is :

The area of the rectangle formed by the perpendiculars from the centre of the standard ellipse to the tangent and normal at its point whose eccentric angles pi/4 is

The area of the rectangle formed by the perpendiculars from the centre of the standard ellipse to the tangent and normal at its point whose eccentric angles pi/4 is

The area of the rectangle formed by the perpendiculars from the centre of the standard ellipse to the tangent and normal at its point whose eccentric angles (pi)/(4) is

If area of rectangle formed by the perpendiculars drawn from centre of ellipse (x^(2))/(9)+(y^(2))/(16)=1 to the tangent and normal at the point (P((3)/(sqrt(2)),2sqrt(2))) on ellipse is ((a)/(b)) (where a and b are coprime numbers) then (a-3b) equals

Find the area of the triangle formed by the tangents from the point (4, 3) to the circle x^2+y^2=9 and the line joining their points of contact.