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A circle passes through point (3, sqrt(7...

A circle passes through point `(3, sqrt(7/2))` and touches the line-pair `x^2 - y^2 - 2x +1 = 0`. Centre of circle lies inside the circle `x^2 + y^2 - 8x + 10y + 15 = 0`. Coordinates of centre of circle are given by (A) `(4,0)` (B) `(5,0)` (C) `(6,0)` (D) `(0,4)`

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