Formaldehyde is treated with methyl magnesium iodide in dry ether and finally with water. The product obtained is

Formaldehyde when reacted with methyl magnesium bromide gives

When n-butyl magnesium iodide is treated with water the product obtained is

" Ethyl acetate is treated with excess of methyl magnesium iodide in dry ether.The reaction mixture is then treated with water.The organic products obtained a "

The product of methyl magnesium iodide and ethanal is hydrolysed. The final product is