At `27^(@)C, K_(p)` value for the reversible reaction `PCl_(5)(g)harrPCl_(3)(g)+Cl_(2)(g)` is 0.65, calculate `K_(c)`.

For PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g), write the expression of K_(c)

For PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g), write the expression of K_(c)

At 473 K, K_(c) for the reaction PCl_(5(g))hArrPCl_(3(g))Cl_(2(g)) is 8.3xx10^(-3) . What will be the value of K_(c) for the formation of PCl_(5) at the same temperature ?

(K_p/K_c) for the given equilibrium is [PCl_5 (g) hArrPCl_3(g) + Cl_2 (g)]

At 473 K, K_(c) for the reaction PCl_(5(g))rArrPCl_(3(g))Cl_(2(g)) is 8.3xx10^(-3) . What will be the value of K_(c) for the formation of PCl_(5) at the same temperature ?

At 473 K, K_(c) for the reaction OCl_(5(g))rArrPCl_(3(g))Cl_(2(g)) is 8.3xx10^(-3) . What will be the value of K_(c) for the formation of PCl_(5) at the same temperature ?