The maximum intensity in Young's double slit experiment is `I_(0)` . What will be the intensity of light in front of one the slits on a screen where path difference is `(lambda)/(4)` ?

Maximum intensity in Young's double slit experiment is I_(0) . If one slit is closed the intensity would be

In Young's double slit experiment, the maximum intensity is I_(0) . What is the intensity at a point on the screen where the path difference between the interfering waves is lamda/4 ?

The maximum intensity in Young's double slit experiment is I_(0) . Distance between the slits is d=2lamda , where lamda is the wavelength of monochromatic light used in experiment. What will be the intensity of light in front of one of the slits on a screen at a distance D=6d ?

The maximum intensity in young's double-slit experiment is I_(0) . Distance between the slit is d = 5 lambda , where lambda is the wavelength of monochromatic light used in the experiment. What will be the intensity of light in front of one of the slits on a screen at a distance D = 10 d ?

The maximum intensity in Young.s double slit experiment is I_0 . Distance between slits is d= 5 lambda , where lambda is the wavelenght of the monochromatic light used in the experiment. What will be the intensity of light in front of one of the slits on a screen at a distance D= 10d .

The maximum intensity in Young’s double slit experiment is I_0 .Distance between the slits is d=2lambda ,where lambda is the wavelength of monochromatic light used in experiment. What will be the intensity of light in front of one of the slits on a screen at a distance D = 6 d?

The intensity at the central maxima in Young' s double slit experiment is I_(0) . Find out the intensity at a point where the path difference is (lambda)/(6) , (lambda)/(4) and (lambda)/(3) .