Given below are the equations of motion of four particles A, B, C and D `x_(A)=6t-3, x_(B)=4t^(2)-2t+3, x_(C)=3t^(3)-2t^(2)+t-7, x_(D)=7 cos 60^(@)-3 sin 30^(@)`
The particle moving with constant acceleration is

At time t, positions of three particles A,B, and C are as follows. x_(A) = 2t + 7, x_(8) = 3t^(2) + 2t + 6, x_(C) = 5t^(3) + 4t Which of them has uniform (constant) acceleration ?

Each of four particles moves along an x axis. Their coordinates (in meters) as function of time (in seconds) are given by Particle 1:x(t) =3.5 -2.7t^(3) Particle :2 x(t)=3.5+2.7 t^(3) particle 3: x(t) =3.5+2.7 t^(2) particle 4: x(t)=3.5-3.4 t -2.7 t^(2) Which of these particles have constant acceleration ?

A particle moves along x-axis and its displacement at any time is given by x(t) = 2t^(3) -3t^(2) + 4t in SI units. The velocity of the particle when its acceleration is zero is

A particle moves along X-axis and its displacement at any time is given by x(t) = 2t^(3) -3t^(2) + 4t in SI units. The velocity of the particle when its acceleration is zero, is

Displacement (x) of a particle is related to time (t) as x = at + b t^(2) - c t^(3) where a,b and c are constant of the motion. The velocity of the particle when its acceleration is zero is given by:

Here are four descriptions of the position (in meters) of a puck as it moves in an xy plane: (1) x=-3t^(2)+4t-2andy=6t^(2)-4t (2) x=-3t^(3)-4t andy=-5t^(2)+6 (3) vecr=2t^(2)hati-(4t+3)hatj (4) vecr=(4t^(3)-2t)hati+hatj Are the x and y acceleration components constant? Is acceleration veca constant?

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?