Of the three independent events `E_1, E_2 and E_3,` the probability that only `E_1` occurs is `alpha,` only `E_2` occurs is `beta` and only `E_3` occurs is `gamma.` Let the probability p that none of events `E_1, E_2 and E_3` occurs satisfy the equations `(alpha-2beta), p=alphabeta and (beta-3gamma) p=2beta gamma.` All the given probabilities are assumed to lie in the interval `(0,1).` Then,`(probability of occurrence of E_1) / (probability of occurrence of E_3)` is equal to

Of the three independent events E_(1),E_(2),and E_(3), the probability that only E_(1) occurs is alpha only E_(2) occurs is beta, and only E_(3) occurs is gamma. Let the probability p that none of events E_(1),E_(2), or E_(3) occurs satisfy the equations (alpha-2beta)p=alpha betaand (beta-3gamma)p=2betagamma. All the given probabilities are assumed to lie in the interval (0,1). Then ("Probability of occurrence of"E_(1))/("Probability of occurence of"E_(3))=

Of the three independent events E_(1),E_(2),and E_(3), the probability that only E_(1) occurs is alpha only E_(2) occurs is beta, and only E_(3) occurs is gamma. Let the probability p that none of events E_(1),E_(2), or E_(3) occurs satisfy the equations (alpha-2beta)p=alpha betaand (beta-3gamma)p=2betagamma. All the given probabilities are assumed to lie in the interval (0,1). Then ("Probability of occurrence of"E_(1))/("Probability of occurence of"E_(3))=

Of the three independent event E_(1),E_(2) and E_(3) , the probability that only E_(1) occurs is alpha , only E_(2) occurs is beta and only E_(3) occurs is gamma . If the probavvility p that none of events E_(1), E_(2) or E_(3) occurs satisfy the equations (alpha - 2beta)p = alpha beta and (beta - 3 gamma) p = 2 beta gamma . All the given probabilities are assumed to lie in the interval (0, 1). Then, ("probability of occurrence of " E_(1))/("probability of occurrence of " E_(3)) is equal to

Of the three independent event E_(1),E_(2) and E_(3) , the probability that only E_(1) occurs is alpha , only E_(2) occurs is beta and only E_(3) occurs is gamma . If the probavvility p that none of events E_(1), E_(2) or E_(3) occurs satisfy the equations (alpha - 2beta)p = alpha beta and (beta - 3 gamma) p = 2 beta gamma . All the given probabilities are assumed to lie in the interval (0, 1). Then, ("probability of occurrence of " E_(1))/("probability of occurrence of " E_(3)) is equal to

Of the three independent event E_(1),E_(2) and E_(3) , the probability that only E_(1) occurs is alpha , only E_(2) occurs is beta and only E_(3) occurs is gamma . If the probavvility p that none of events E_(1), E_(2) or E_(3) occurs satisfy the equations (alpha - 2beta)p = alpha beta and (beta - 3 gamma) p = 2 beta gamma . All the given probabilities are assumed to lie in the interval (0, 1). Then, ("probability of occurrence of " E_(1))/("probability of occurrence of " E_(3)) is equal to

Of the three independent event E_(1),E_(2) and E_(3) , the probability that only E_(1) occurs is alpha , only E_(2) occurs is beta and only E_(3) occurs is gamma . If the probavvility p that none of events E_(1), E_(2) or E_(3) occurs satisfy the equations (alpha - 2beta)p = alpha beta and (beta - 3 gamma) p = 2 beta gamma . All the given probabilities are assumed to lie in the interval (0, 1). Then, ("probability of occurrence of " E_(1))/("probability of occurrence of " E_(3)) is equal to

Of the three independent events E_(1),E_(2),and E_(3), the probability that only E_(1) occurs is alpha only E_(2) occurs is beta, and only E_(3) occurs is gamma. Let the probability p that none of events E_(1),E_(2), or E_(3) occurs satisfy the equations (alpha-2beta)p=alpha betaand (beta-3gamma)p=betagamma. All the given probabilities are assumed to lie in the interval (0,1). Then ("Probability of occurrence of"E_(1))/("Probability of occurence of"E_(3))=______.

There are two independent events E_1 and E_2 and P(E_1)=0.30 , P(E_2)=0.60 find the probability that both E_1 and E_2 occur.