Show that the de Broglie wavelength of electron of energy K is given by `lamda = (h)/(sqrt(2mK))`.

The de-Broglie wavelength lamda

What is de-Broglie wavelength of electron having energy 10 KeV ?

Show that the do Broglie wavelength lamda of an electron of energy E is given by the relation lamda = =h/(sqrt2mE)

Show.that the de-Broglie wavelength lambda of electrons of energy E is given by the relation, lambda = h/sqrt(2mE) .

Show that the de-Broglie wavelength lambda of electrons of energy E is givne by the relation: lambda= h /(sqrt(2 m E)) .

Calculate the de Broglie wavelength of an electron of kinetic energy 500 eV.

Show that de Broglie wavelength of electrons accelerated V volt is very nearly given by: lamda("in Ã…")=((150)/(V))^(1//2)