In the figure (i) below, ABCD is a square. E is the midpoint of CB. AF is drawn perpendicular to DE. If the side of the square is 2013 cm, the length of FB is (in cm)

ABCD is a square.F is the midpoint of AB and BE is one fourth of BC. If the area of DFBE is 36 sq.cm.Find the length of AC.

In the figure given below, ABCD is a square of side 7 cm. BD is an arc of a circle of radius AB.

In the figure ABCD is a square of side 8cm and PMLAB. Then the length of MC is

ABCD is a square . W is the mid point of AB side of square is 16 cm. Find the radius of circle in figure

In Figure - 5, ABCD is a square with side 7 cm A circle is drawn circumscribing the square. Find the area of the shaded region.

In Figure - 5, ABCD is a square with side 7 cm A circle is drawn circumscribing the square. Find the area of the shaded region.

In the figure given below, ABCD is a square of side 10 cm and a circle is inscribed in it. Find the area of the shaded part as shown in the figure.

In the figure given below, ABCD is a square of side 14 cm with E,F,G and H as the mid points of sides. The area of EFGH is :

In the given figure, ABCD is a square. M is the mid-point of AB and PQ is perpendicular to CM. CB produced meets PQ at point Q. Prove that : (i) PA = BQ (ii) CP = AB + PA