The first orbital of H is represented by: `psi=(1)/(sqrtr)((1)/(a_(0)))^(3//2)e^(-r//a_(0))`, where `a_(0)` is Bohr's radius. The probability of finding the electron at a distance r, from the nucleus in the region dV is :

The first orbital of H is represented by: psi=(1)/(sqrtpi)((1)/(a_(0)))^(3//2)e^(-r//a_(0)) , where a_(0) is Bohr's radius. The probability of finding the electron at a distance r, from the nucleus in the region dV is :

The first orbital of H is represented by psi=2(1/a_0)^(3/2) e^-(r/a_0) where a_0 is Bohr's radius the probability of finding the electron at a distance r from the nucleus in the region dV is

The first obrital of H or H like atom is represencted by psi = 1/( sqrt pi) (Z/a_0) ^(3//2) e^(-ze//a_0) where a_0 = Bohr's orbit . The actual probability of fiding the elercrton at a distance r form the nucleus is :

The radial wave function for 1 s electron in H-atom is R=(2)/a_(0)^(3//2)e^(-r//a_(0)) where a_(0) =radius of 1^(st) orbit of H-atom . The ratio of probablitiy of 1^(st) electron in hyrogen atom at distance a_(0) from nucleus to that at distance a_(0)/2 from nucleus.

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

For an electron in a hydrogen atom, the wave function psi is proportional to exp -r//a_(0) , where a_(0) is the Bohr radius. Find the ratio of probability of finding the electron at the nucleus to the probability of finding it at a_(0) .

The wave function for 1s orbital of hydrogen atom is given by: Psi_(1s)=(pi)/sqrt2e^(-r//a_(0)) Where, a_(0) = Radius of first Bohar orbit r= Distance from the nucleus (Probability of finding the ekectron varies with respect to it) What will be the ratio of probability of finding rhe electron at the nucleus to first Bohr's orbit a_(0) ?