Anti logarithm of `0.75` to the base 16 has the value equal to

{:(Column -I,Column -II),((A)"Anti logarithm of" (0.bar(6))"to the base 27 has the value equal to",(P)5),((B)"Characteristic of the logarithm of 2008 to the base 2 is",(Q)7),((C)"The value of b satisfying the equation",(R)9),(log_(e)2.log_(b)625=log_(10)16.log_(e)10 is,),((D)"Number of naughts after decimal before a significant figure",(S)10),("comes in the number" ((5)/(6))^(100)is,):}

{:(Column -I,Column -II),((A)"Anti logarithm of" (0.bar(6))"to the base 27 has the value equal to",(P)5),((B)"Characteristic of the logarithm of 2008 to the base 2 is",(Q)7),((C)"The value of b satisfying the equation",(R)9),(log_(e)2.log_(b)625=log_(10)16.log_(e)10 is,),((D)"Number of naughts after decimal before a significant figure",(S)10),("comes in the number" ((5)/(6))^(100)is,):}

. Logarithm of 144 to the base 2sqrt3 is

Determine logarithm of 1728 to the base 2sqrt3

Find the logarithm of 324 to the base 3sqrt 2

If the logarithm of 1728 to the base a is 6 Find a

Find the logarithm of 1728 to the base 2sqrt3 .

The logarithm of 0.00001 to the base 0.01 is equal to a.-(5)/(2) b.(5)/(2) c.3