Particles having energy of several hundred `MeV` are known as

An alpha -particle having energy = 10 meV collides with a nucleus of atomic number 50. The distance of the closest approach is

An alpha -particle having kinetic energy of 7.5 MeV is scattered by gold (Z=79) mucleus through 180^(@) . Calculate the distance of closest approach.

An alpha particle having kinetic energy equal to 8.7 MeV is projected towards the nucleus of copper with Z=29.Calculate its distance of closet approach.

Consider a particle , beta particle and gamma - rays , each having an energy of 0.5 MeV . In increase order of panetrating poewr , the radiation are .

Consider alpha particle , beta particle and gamma - rays , each having an energy of 0.5 MeV . In increase order of panetrating power , the radiation are .

A nucleus of mass 218 amu in Free State decays to emit an alpha -particle. Kinetic energy of the beta- particle emitted is 6.7 MeV . The recoil energy (in MeV) of the daughter nucleus is