When a body is projected from a level ground the ratio of its speed in the vertical and horizontal direction is 4 3. If the velocity of projection is u, the time after which the ratio of the velocities in the vertical and horizontal directions are reversed is

Give the horizontal and vertical components of velocity of projection

A body is projected in vertically upwards direction with a speed u. Find the time taken

STATEMENT-1: A body is projected from the ground with a velocity v at an angle with the horizontal direction, it reaches a maximum height (H) and reaches the ground after a time T = 2u sin theta//g because STATEMENT-2: The vertical and horizontal motions can be treated independently

(A): For a body projected horizontally from the top of a tower, the velocity on reaching the ground depends both on velocity of projection and height of the tower. (R): For a projectile velocity varies both in horizontal and vertical directions.

A body is projected horizontally from the top of a building of height h. Velocity of projection is u. Find the time it will take to reach the ground ,

A particle is projected from a point on the level ground and its height is h when at horizontal distances a and 2 a from its point of projection. Find the velocity of projection.

A particle is projected from a point on the level ground and its height is h when at horizontal distances a and 2 a from its point of projection. Find the velocity of projection.