The electric intensity of outside a charged sphere of radius R at a distance `r (r gt R)` is

The electric field intensity |vecE| at any point inside a charged sphere of radius r is

A point charge Q is placed outside a hollow spherical conductor of radius R , at a distance r (r gt R) from its centre C . The field at C due to the inducted charges on the conductor is

A point charge Q is placed outside a hollow spherical conductor of radius R , at a distance r (r gt R) from its centre C . The field at C due to the induced charges on the conductor is

The electric intensity due to a uniformly charged infinite cylinder of radius R , at a distance r(gt R) , from its axis is proportional to

Show that electric intensity at a point outside a charged sphere is given by, E = (sigma R^2)/(in_0 kr^2)

The gravitational potential at a point outside the solid sphere of radius "R" and at a distance of "r" will be :

A non conducting solid sphere of radius R is uniformly charged. The magnitude of electric field intensity due to the sphre at a distance r from its centre

Assertion: Electric potential on the surface of a charged sphere of radius R is V. Then electric field at distance r=R/2 from centre is V/(2R) . Charge is distributed uniformly over the volume. Reason: From centre to surface, electric field varies linearly with r. Here r is distance from centre.

Assertion: Electric potential on the surface of a charged sphere of radius R is V. Then electric field at distance r=R/2 from centre is V/(2R) . Charge is distributed uniformly over the volume. Reason: From centre to surface, electric field varies linearly with r. Here r is distance from centre.

If sigma is surface density of charge on the charged cylinder of radius R, then electric intensity E at outer point at a distance r from its axis is