The gravitational acceleration on the surface of earth of radius R and mean density `rho` is

The escape velocity from the surface of the earth of radius R and density rho

The escape velocity from the surface of the earth of radius R and density rho

Show that the escape velocity of a body from the surface of a planet of radius R and mean density rho is Rfrac(sqrt8pirhoG)(3) OR Show that the escape velocity of a body from the surface of the earth is 2Rfrac(sqrt2pirhoG)(3) , where R is the radius of the earth and rho is the mean density of the earth. OR Obtain formula of escape velocity of a body at rest on the earth's surface in terms of mean density of erth.

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at surface of planet is half of the acceleration at surface of earth, if radius of the earth is R. The radius of planet would be